Which of the following statement is true?

Options

A. `SbF_(4)^(-) and SF_(4)` are isostructural
B. In `IOF_(5)` the hybridization of central atom is `sp^(3)d^(2)`
C. Double bond(s) in `SOF_(4) and XeO_(3)F_(2)`, is/are occupying equatorial position(s) of their
D. All of these

Answer

To determine which of the statements is true, we will analyze each statement one by one based on the information provided in the transcript.

### Step-by-Step Solution:

1. **Statement 1: SbF4- and SF4 are isostructural.**
- **Analysis:**
- For SbF4- (antimony tetrafluoride):
- Antimony (Sb) has 5 valence electrons. With a -1 charge, it has 6 valence electrons.
- It forms 4 bonds with fluorine atoms and has 1 lone pair.
- Therefore, the steric number (number of bond pairs + lone pairs) = 4 (bond pairs) + 1 (lone pair) = 5.
- This corresponds to sp3d hybridization and a trigonal bipyramidal geometry.

- For SF4 (sulfur tetrafluoride):
- Sulfur (S) has 6 valence electrons.
- It forms 4 bonds with fluorine atoms and has 1 lone pair.
- The steric number is also 4 (bond pairs) + 1 (lone pair) = 5.
- This also corresponds to sp3d hybridization and a trigonal bipyramidal geometry.

- **Conclusion:** Since both have the same steric number and hybridization, they are isostructural. **This statement is true.**

2. **Statement 2: In IOF5, the hybridization of the central atom is sp3d2.**
- **Analysis:**
- Iodine (I) has 7 valence electrons.
- In IOF5, iodine forms 5 bonds with fluorine and 1 bond with oxygen.
- The steric number = 5 (bond pairs) + 1 (lone pair) = 6.
- This corresponds to sp3d2 hybridization, which is correct.

- **Conclusion:** This statement is also true.

3. **Statement 3: In SOF4 and XeO3F2, the double bonds occupy equatorial positions.**
- **Analysis:**
- For SOF4:
- Sulfur has 6 valence electrons and forms 4 bonds with fluorine and 1 double bond with oxygen.
- The steric number = 5 (4 bond pairs + 1 double bond).
- The double bond will occupy an equatorial position due to the presence of more electronegative fluorine atoms.

- For XeO3F2:
- Xenon has 8 valence electrons and forms 3 double bonds with oxygen and 2 bonds with fluorine.
- The steric number = 5 (3 double bonds + 2 bond pairs).
- The double bonds will also occupy equatorial positions.

- **Conclusion:** This statement is true.

### Final Conclusion:
All three statements are true based on the analysis. However, if the question requires identifying just one true statement, we can conclude that **Statement 1 is true**.