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The K(alpha) X-ray emission line of tung...

The `K_(alpha) X`-ray emission line of tungsten occurs at `lambda = 0.021 nm`. The energy difference between K and L levels in this aotm is about : `0.51 MeV`

A

0.51 MeV

B

1.2 MeV

C

59 keV

D

13.6 eV

Text Solution

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The correct Answer is:
C
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The K_(alpha) X-ray emission line of lungsten accurs at lambda = 0.021 nm . What is the energy difference between K and L levels in the atom?

The wavelength of the K_(alpha) line from iron is 193 pm. What is the energy difference between the two states of the iron atom that give rise to this transition?

Knowledge Check

  • The binding energy of the innermost electron in tungsten is 40 keV . To produce characteristic X - rays using a tungsten target in an X - rays tube the potential difference V between the cathode and the anti - cathode should be

    A
    `V lt 40 kV`
    B
    `V le 40 kV`
    C
    `V gt 40 kV`
    D
    `V gt//lt40 kv`

  • If lambda_(Cu) is the wavelength of K_(alpha) X-ray line of copper (atomic number 29 ) and lambda_(Mo) is the wavelength of the K_(alpha) X-ray line of molybdenum (atomic number 42 ),then the ratio lambda_(Cu)//lambda_(Mo) is close to

    A
    `1.99`
    B
    `2.14`
    C
    `0.50`
    D
    `0.48`

  • The K_(alpha) line obtained for molybdenum (Z = 42) is 0.71 Å. Then, the wavelength of the K_(alpha) line of copper (Z = 29) is

    A
    2.14 Å
    B
    1.52 Å
    C
    1.04 Å
    D
    1.71 Å

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    Which element has K_(alpha) x-ray line whose wavelength is 0.180 nm?

    The wavelength of k_(alpha) X- rays produced by an X - rays tube is 0.76 Å . The atomic number of the anode material of the tube is …….

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    The wavelength of K_(alpha) X-ray of tungsten is 21.3 pm. It takes 11.3 keV to knock out an electron from the L shell ofa tungsten atom. What should be the minimum accelerating voltage across an X-ray tube having tungsten target which allows production of k_(alpha) X-ray ?

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