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Shiow that [(ptoq)^^(qto r)] to ( p to r...

Shiow that `[(ptoq)^^(qto r)] to ( p to r)`is a tautology

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Knowledge Check

  • If (p wedge q) ox (p o+ q) is a tautology, then

    A
    `ox is rarr and o+ is vv`
    B
    `ox is ^^ and o+ is ^^`
    C
    `ox is vv and o+ is vv`
    D
    `ox is vv and o+ is ^^`

  • Consider : Statement I: (p^^~q)^^(~p^^q) is a fallacy Statement II: (ptoq)harr(~q to ~p) is a tautology

    A
    Statement-1 is true, statement 2 is true, statement 2 is a correct explanation for statement 1
    B
    Statement 1 is true, statement-2 is true, statement 2 is not a correct explanation for statement 1
    C
    Statement 1 is true , statement 2 is false,
    D
    statement 1 is false, statement 2 is true

  • Consider following statements Statement - I : (p^~a)^(vpng) is a fallacy. Statement - II : (p to q) harr (~qto~p) is a tautology.

    A
    Statement - I is true, statement -II is false.
    B
    Statement - I is false, Statement - II is true.
    C
    Statement - I true, Statement - II is true, Statement - II is a correct explanation for Statement - I.
    D
    Statement - I is true, Statement - II is true, Statement - II is not a correct explanation for Statement - I.

    • Similar Questions

    Explore conceptually related problems

    Show that (i) ~ [ p ^^ ( ~p) ] is a tautology (ii) ~ [ p vee ( ~ p)] is a contradication.

    Show that (i) p to (pvvq) is a tautology (ii) (pvvq) ^^(~ p ^^~q) is a contradiction

    The statement (p^^(p to q) ^^ (q to r)) to r is

    Verify that the statement P vee ~( p ^^ q) is a tautology.

    Let p,q,r be the statements p: X is a rectangle, q: x is a square, r:p to q Show that p to r is not a tautology.

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