Shiow that `[(ptoq)^^(qto r)] to ( p to r)`is a tautology

Show that [(ptoq)^^(qto r)] to ( p to r) is a tautology

Show that (pvvq) to r -= (p to r) ^^ (q to r)

If (p wedge q) ox (p o+ q) is a tautology, then

Show that (i) ~ [ p ^^ ( ~p) ] is a tautology (ii) ~ [ p vee ( ~ p)] is a contradication.

Show that (i) p to (pvvq) is a tautology (ii) (pvvq) ^^(~ p ^^~q) is a contradiction

The statement (p^^(p to q) ^^ (q to r)) to r is

Consider : Statement I: (p^^~q)^^(~p^^q) is a fallacy Statement II: (ptoq)harr(~q to ~p) is a tautology

Verify that the statement P vee ~( p ^^ q) is a tautology.

Let p,q,r be the statements p: X is a rectangle, q: x is a square, r:p to q Show that p to r is not a tautology.