Home
Class 12
MATHS
Let z be a complex number satisfying z^...

Let z be a complex number satisfying `z^(2) + 2zlambda + 1=0` , where `lambda ` is a parameter which can take any real value.
The roots of this equation lie on a certain circle if

A

`-1lt lambda lt 1`

B

`lambda gt 1`

C

`lambda lt 1`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MATHEMATICS TIPS

    FIITJEE|Exercise NUMERICAL RASED QUESTIONS|24 Videos

  • MATHEMATICS TIPS

    FIITJEE|Exercise NUMERICAL DECIMAL BASED QUESTIONS|21 Videos

  • MATHEMATICS TIPS

    FIITJEE|Exercise PARAGRAPH BASED (MULTIPLE CHOICE) (COMPERHENSION - XV)|2 Videos

  • MATHEMATICS

    FIITJEE|Exercise NUMERICAL DECIMAL BASED QUESTIONS|15 Videos

  • MATRICES

    FIITJEE|Exercise NUMERICAL BASED|3 Videos

Similar Questions

Explore conceptually related problems

Let z be a complex number satisfying the equation z^(2)-(3+i)z+lambda+2i=0, whre lambdain R and non -real root.

Let z be a complex number satisfying the equation z^(2)-(3+i)z+m+2i=0, wherem in R Suppose the equation has a real root.Then root non-real root.

Knowledge Check

  • Let z be a complex number satisfying z^(2) + 2zlambda + 1=0 , where lambda is a parameter which can take any real value. One root lies inside the unit circle and one outside if

    A
    `-1 lt lambda lt 1`
    B
    `lambda gt 1`
    C
    `lambda lt 1`
    D
    none of these

  • Let z be a complex number satisfying |z+16|=4|z+1| . Then

    A
    `|z|=4`
    B
    `|z|=5`
    C
    `|z|=6`
    D
    `3 lt |z| lt68`

  • In the equation z^(2)+2lambda z+1=0,lambda is a parameter which can take any real value, then For every large value of lambda, the roots are approximately

    A
    `-2lambda,(1)/(lambda)`
    B
    `-lambda,-(1)/(lambda)`
    C
    `-2lambda,-(1)/(2lambda)`
    D
    none of these

    • Similar Questions

    Explore conceptually related problems

    Let z be a complex number satisfying 2z+|z|=2+6i .Then the imaginary part of z is

    Let z be a complex number satisfying z^(117)=1 then minimum value of |z-omega| (where omega is cube root of unity) is

    The complex number z satisfying the equation |z-i|=|z+1|=1

    Find a complex number z satisfying the equation z+sqrt(2)|z+1|+i=0

    z is a complex number satisfying z^(4)+z^(3)+2z^(2)+z+1=0 , then |z| is equal to

    Home
    Profile