Home
Class 12
PHYSICS
A person travels along a straight road f...

A person travels along a straight road for the first `(t)/(3)` time with a speed `v_(1)` and for next `(2t)/(3)` time with a speed `v_(2)`. Then the mean speed v is given by

A

`v=(v_(1)+2v_(2))/(3)`

B

`(1)/(v)=(1)/(3v_(1))+(2)/(3v_(2))`

C

`v=(1)/(3)sqrt(2v_(1)v_(2))`

D

`v=sqrt((3v_(2))/(2v_(1)))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the mean speed \( v \) of a person who travels along a straight road for different time intervals and speeds, we can follow these steps: ### Step 1: Understand the problem The person travels for the first \( \frac{t}{3} \) time with speed \( v_1 \) and for the next \( \frac{2t}{3} \) time with speed \( v_2 \). We need to find the mean speed over the total time. ### Step 2: Calculate the distance for each segment 1. **Distance for the first segment**: - Time = \( \frac{t}{3} \) - Speed = \( v_1 \) - Distance \( D_1 = v_1 \times \text{time} = v_1 \times \frac{t}{3} = \frac{v_1 t}{3} \) 2. **Distance for the second segment**: - Time = \( \frac{2t}{3} \) - Speed = \( v_2 \) - Distance \( D_2 = v_2 \times \text{time} = v_2 \times \frac{2t}{3} = \frac{2v_2 t}{3} \) ### Step 3: Calculate the total distance - Total distance \( D \) is the sum of \( D_1 \) and \( D_2 \): \[ D = D_1 + D_2 = \frac{v_1 t}{3} + \frac{2v_2 t}{3} = \frac{(v_1 + 2v_2)t}{3} \] ### Step 4: Calculate the total time - Total time \( T \) is the sum of the two time intervals: \[ T = \frac{t}{3} + \frac{2t}{3} = t \] ### Step 5: Calculate the mean speed - Mean speed \( v \) is given by the formula: \[ v = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{D}{T} \] - Substituting the values we calculated: \[ v = \frac{\frac{(v_1 + 2v_2)t}{3}}{t} = \frac{(v_1 + 2v_2)}{3} \] ### Final Result Thus, the mean speed \( v \) is: \[ v = \frac{v_1 + 2v_2}{3} \] ---
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - B)|33 Videos
  • MOTION IN A STRAIGHT LINE

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - C)|37 Videos
  • MOTION IN A STRAIGHT LINE

    AAKASH INSTITUTE|Exercise EXERCISE|30 Videos
  • MOTION IN A PLANE

    AAKASH INSTITUTE|Exercise Assignement section -J (Aakash Challengers Questions)|4 Videos
  • MOTION IN STRAIGHT LINE

    AAKASH INSTITUTE|Exercise Assignment (SECTION - J)|2 Videos

Similar Questions

Explore conceptually related problems

A person travels along a straight road for the first half length with a constant speed v_(1) and the second half length with a constant speed v_(2) . The average speed V is:

A partical moves from A to B for the first one-third with speed v_(1) and the next two-third time with speed v_(2) . Find the average speed.

A person travels along a straight road for the first half length with a velocity v_(1) and the second half length with velocity v_(2) . What is the mean velocity of the person ?

A particle moves in a straight line from A to B (a) for the first half of distance with speed v_(1) and the next half of distance with speed v_(2) . (b) for the first one-third distance with speed v_(1) and the next two-third distance with speed v_(2) . (c ) for the first one-fourth distance with speed v_(0) , the next half of distance with speed 2v_(0) and the last one-fourth distance with speed 3v_(0) . Find the average speed in each case.

A particle travels first half of the total time with speed v_1 and second half time with speed v_2. Find the average speed during the complete journey.

If a particle travels the first half distance with speed v_(1) and second half distance with speed v_(2) . Find its average speed during journey.

A particle moves in a straight line from A to B with speed v_(1) and then from B to A with speed v_(2) . Find the average velocity and average speed.

A car complete the first half of its journey with speed v_(1), and the rest half with speed v_(2). The average speed of the car in whole journey:

AAKASH INSTITUTE-MOTION IN A STRAIGHT LINE-ASSIGNMENT (SECTION - A)
  1. The position of a particle moving along x-axis is given by x = 10t - 2...

    Text Solution

    |

  2. A car moves with speed 60 km//h for 1 hour in east direction and with ...

    Text Solution

    |

  3. A person travels along a straight road for the first (t)/(3) time with...

    Text Solution

    |

  4. If the displacement of a particle varies with time as sqrt x = t+ 3

    Text Solution

    |

  5. A boat covers certain distance between two spots on a river taking 't(...

    Text Solution

    |

  6. A particle starts moving with acceleration 2 m//s^(2). Distance trav...

    Text Solution

    |

  7. The two ends of a train moving with constant acceleration pass a certa...

    Text Solution

    |

  8. The initial velocity of a particle is u (at t = 0) and the acceleratio...

    Text Solution

    |

  9. A trian starts from rest from a station with acceleration 0.2 m/s^(2) ...

    Text Solution

    |

  10. The position x of particle moving along x-axis varies with time t as x...

    Text Solution

    |

  11. A particle moves in a straight line and its position x at time t is g...

    Text Solution

    |

  12. A body is projected vertically upward direction from the surface of ea...

    Text Solution

    |

  13. A particle start moving from rest state along a straight line under th...

    Text Solution

    |

  14. A body is projected vertically upward with speed 40m/s. The distance t...

    Text Solution

    |

  15. A body is moving with variable acceleartion (a) along a straight line....

    Text Solution

    |

  16. A body is projected vertically upward with speed 10 m//s and other at ...

    Text Solution

    |

  17. The position of a particle moving along x-axis given by x=(-2t^(3)-3t^...

    Text Solution

    |

  18. A car travelling at a speed of 30 km / hour is brought to a halt in 8 ...

    Text Solution

    |

  19. A particle is thrown with any velocity vertically upward, the distance...

    Text Solution

    |

  20. A body is thrown vertically upwards and takes 5 seconds to reach maxim...

    Text Solution

    |