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The maximum angle to the horizontal at w...

The maximum angle to the horizontal at which a stone can be thrown so that it always moves away from the thrower will be :

Text Solution

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The correct Answer is:
`sin^(-1) (sqrt(8/9)`
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Knowledge Check

  • A small ball thrown at an initial velocity v_(0) at an angle alpha to the horizontal strikes elastically with a smooth vertical wall moving towards it at a horizontal velocity v and returns to the point from which it was thrown. Determine the time t from the beginning of motions to the moment of impact with vertical wall. Neglect friction losses.

    A
    `t=(v_(0)sinalpha(v_(0)cosalpha+2v))/(g(v_(0)cosalpha+v))`
    B
    `t=(v_(0)sinalpha(v_(0)cosalpha-2v))/(g(v_(0)cosalpha+v))`
    C
    `t=(v_(0)sinalpha(v_(0)cosalpha+2v))/(g(v_(0)cosalpha-v))`
    D
    `t=(v_(0)cosalpha(v_(0)sinalpha+2v))/(g(v_(0)sinalpha+v))`

  • A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be:

    A
    ` 20 sqrt2 ` m
    B
    ` 10 `m
    C
    ` 10 sqrt2 m `
    D
    ` 20 m `

  • A stone is projected with an initial velocity at some angle to the horizontal. A small piece separates from the stone before the stone reaches its maximum height. Then the piece will

    A
    fall to the ground
    B
    fly horizontally initially and will then describe a parabolic path
    C
    fly side by side with the parent stone along a parabolic path
    D
    lag behind the parent stone increasing the distance from it.