Calculate the molal depression constant ...

Calculate the molal depression constant of a solvent which has freezing point `16.6^(@)C` and latent heat of fusion `180.75 "J g"^(-1)` :

2.68

3.86

4.68

2.86

Text Solution

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The correct Answer is:

`K_(f)=(RT_(0)^(2))/(1000L)" "T_(0)=273+16.6=289.6K`
`=(8.314xx(289.6)^(2))/(1000xx180.75)=3.86`]

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