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Concentrated sulphuric acid has density ...

Concentrated sulphuric acid has density of 1.9 g/mL and 99% `H_(2)SO_(4)` by mass. Calculate the molarity of the acid.

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To calculate the molarity of concentrated sulfuric acid, we will follow these steps: ### Step 1: Understand the Given Information - Density of concentrated sulfuric acid = 1.9 g/mL - Mass percentage of H₂SO₄ = 99% - We will assume we have 100 g of the solution for easier calculations. ### Step 2: Calculate the Mass of H₂SO₄ Since the solution is 99% H₂SO₄ by mass: \[ \text{Mass of H₂SO₄} = 99\% \text{ of 100 g} = 99 \text{ g} \] ### Step 3: Calculate the Volume of the Solution Using the density formula: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] We can rearrange this to find the volume: \[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} = \frac{100 \text{ g}}{1.9 \text{ g/mL}} \approx 52.63 \text{ mL} \] Now, convert this volume from mL to L: \[ \text{Volume in L} = \frac{52.63 \text{ mL}}{1000} \approx 0.05263 \text{ L} \] ### Step 4: Calculate the Number of Moles of H₂SO₄ To find the number of moles, we use the molar mass of H₂SO₄: \[ \text{Molar mass of H₂SO₄} = 2(1) + 32 + 4(16) = 98 \text{ g/mol} \] Now, calculate the number of moles: \[ \text{Number of moles of H₂SO₄} = \frac{\text{Mass}}{\text{Molar mass}} = \frac{99 \text{ g}}{98 \text{ g/mol}} \approx 1.01 \text{ mol} \] ### Step 5: Calculate the Molarity Molarity (M) is defined as the number of moles of solute per liter of solution: \[ \text{Molarity} = \frac{\text{Number of moles}}{\text{Volume in L}} = \frac{1.01 \text{ mol}}{0.05263 \text{ L}} \approx 19.19 \text{ M} \] ### Final Answer The molarity of the concentrated sulfuric acid is approximately **19.19 M**. ---
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A bottle of commercial sulphuric acid (density = 1.787 g mL^(-1)) is labelled as 86 per cent by mass What is the molarity of the acid ? What volume of the acid has to be used to make 1 liotre of 0.2 M H_(2)SO_(4) ?

A bottle of concentrated sulphuric acid (density 1.80 g cm^(-3) ) is labelled as 86% by weight. What is the molarity of the solution ?

Knowledge Check

  • The concentrated sulphuric acid that is peddled commercially is 95% H_(2)SO_(4) by weight. If the density of this commerical acid is 1.834 g cm^(-3) , the molarity of this solution is

    A
    `17.8 M`
    B
    `15.7 M`
    C
    `10.5M`
    D
    `12.0M`
  • A sample of commercial sulphuric acid is 98% H_(2) SO_(4) by mass. Calculate the mole fractions of H_(2) SO_(4) and H_(2) O .

    A
    `0.9, 0.1`
    B
    `0.1, 0.9`
    C
    `0.2, 0.8`
    D
    `0.8, 0.2`
  • Conc. H SO_4 has density of 1.9 g mL^(-1) and is 99% by weight. Calculate the molarity of H_2SO_4 " (Mol wt of " H_2SO_4 = 98 g mol^(-1) ).

    A
    2.4 M
    B
    24.2 M
    C
    19.1 M
    D
    9.8 M
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    Commercially available sulphuric acid contains 93% acid by mass and has a density of 1.84 g mL^(-1) . Calculate (i) the molarity of the solution (ii) volume of concentrated acid required to prepare 2.5 L of 0.50 M H_(2)SO_(4)

    A bottle of commercial sulphuric acid (density 1.787 g/mL) is labelled as 86 % by weight . What is the molarity of the acid ? What volume of the acid has to be used to make 1 litre of 0.2 " M " H_(2)SO_(4) ?

    Molarity: A sample of commercial sulphuric acid is 98% H_(2) SO_(4) by mass and its specfic gravity is 1.84 . Caculate the molartiy of this sulburic acid solution. Strategy: The density of a solution (grams per milliliter) is numercially equal to its specific gravity. Thus, the density of the solution is 98% H_(2) SO_(4) by mass. Thus, every 100g of soultuon contains 98g of pure H_(2) SO_(4) . From the mass of H_(2) SO_(4) . we calculate its moles and from the density , we calculate its volume. Finally, we calculate molartity using its definition.

    Commerically available concentrated hydrochloric acid contains 38% HCl by mass and density 1.19 g cm^(-3) . Calculate the molarity of this solution.

    Concentrated aqueous sulphuric acid is 98% H_(2)SO_(4) by mass and has a density of "1.80 g mL"^(-1) . Volume of the acid required to make one litre of 0.1 M H_(2)SO_(4) solution is