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Depression in freezing point is 6K for N...

Depression in freezing point is 6K for NaCl solution. If `K_(f)` for water is `1.86 "K kg mol"^(-1)`, amount of NaCl dissolved in 1kg water is :

A

3.42

B

1.62

C

3.24

D

1.71

Text Solution

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The correct Answer is:
B
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45 g of ethylene glycol (C_(2)H_(6)O_(2)) is mixed with 600 g water. Calculate (a) freezing point depression (b) freezing point of the solution (K_(f)" for water = 1.86 K kg mol"^(-1)," Atomic masses : C = 12, H = 1, O = 16 amu") .

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Knowledge Check

  • A solution of sucross (molar mass = 342 g "mol"^(-1) ) has been prepared by dissolving 68.4 g of sucrose in one kg of water. K_(f) for water is "1.86 K kg mol"^(-1) and vapour pressure of water at 298 K is 0.024 atm. If on dissolving the above amount of NaCl in 1 kg of water, the freezing point is found to be -0.344^(@)C , the percentage dissociation of NaCl in the solution is

    A
    `75%`
    B
    `80%`
    C
    `85%`
    D
    `90%`
  • A solution of sucross (molar mass = 342 g "mol"^(-1) ) has been prepared by dissolving 68.4 g of sucrose in one kg of water. K_(f) for water is "1.86 K kg mol"^(-1) and vapour pressure of water at 298 K is 0.024 atm. The freezing point of the solution will be

    A
    `-0.684^(@)C`
    B
    `-0.342^(@)C`
    C
    `-0.372^(@)C`
    D
    `-0.186^(@)C`
  • The freezing point of 0.05 molal solution of non- electrolyte in water is _____. (K_(f) = 1.86 K Kg mol ^(-1))

    A
    `271.3 K`
    B
    `0.93K`
    C
    `272.907 K`
    D
    `-0.0093K`
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