A toroid of n turns, mean radius R and c...

A toroid of n turns, mean radius R and cross-sectional radius a carries current I. It is placed on a horizontal table taken as x-y plane. Its magnetic moment `vecM`

is non-zero and points in the z-direction by symmetry

points along the axis of the toroid `(vec(M)=mhatphi)`

is zero, otherwise there would be a field falling as `(1)/(r^(3))` at large distances outside the toroid

is pointing radially outwards.

Text Solution

Verified by Experts

The correct Answer is:

In a toroid magnetic field is only confined inside the body of toroid in the form of conentric magnetic lines of force and outside the toroid magnetic field is zero.

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A circular coil of n turns and radius r carries a current I. The magnetic field at the center is

`(mu_0nI)/(r)`

`(mu_0nI)/(2r)`

`(2mu_0nI)/(r)`

`(mu_0nI)/(4r)`

The radius of a circular loop is r and a current I is flowing is it. The equivalent magnetic moment will be

`2 pi Ir`

`I pi r^(2)`

`(1)/(r^(2))`

A toroid of mean radius 'a', cross section radius 'r' and total number of turns N. It carries a current 'I'. The torque experienced by the toroid if a uniform magnetic field of strength B is applied.

is zero

is Bi N `pir^(2)`

is B I `N pi a^(2)`

depends on the direction of magnetic field.