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Assertion (A ) : The degree of ionizatio...

Assertion (A ) `:` The degree of ionization of water is small at `25^(@)C` , only about one of every `10^(7)` molecules in pure water is ionized at any instant
Reason (R ) `:` In pure water at `25^(@)C ` the molar concentration of water is essentially constant.

A

Both A and R true and R is the correct explanation of A

B

Both A and R are true but R is not a correct explanation of A

C

A is true but R is false

D

A is false but R is true

Text Solution

Verified by Experts

The correct Answer is:
B
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Calculate the degree of ionization of pure water at 25^@C .

The degree of dissociation of pure water at 18^@C is found to be 1.8 xx 10^(-9) . Find ionic product of water and its dissociation constant at 18^@C .

Knowledge Check

  • The degree of dissociation of 100 mL of pure water at 25^(@)C is

    A
    `1.8xx10^(-16)`
    B
    `1xx10^(-14)`
    C
    `1.8xx10^(-9)`
    D
    `1.0`

  • If HCl is added to pure water at 25^(@)C the ionic product of water will be

    A
    `gt 10^(-14)`
    B
    `lt 10^(-14)`
    C
    `10^(-14)`
    D
    `gt 10^(-10)`

  • On adding an acid in a sample of pure water at 25^(@)C :

    A
    the ionic product of water becomes greater than `10^(14)M^(2)`
    B
    the ionic product of water remains `10^(-14)M^(2)`
    C
    `[H^(+)]` becomes greater than `[OH^(-)]`
    D
    `[OH^(-)]` becomes zero.

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