The chloroform reacts with NaOH to give

Options

A. `CH_(3)COONa`
B. Sodium oxalate
C. `CH_(3)OH`
D. HCOONa

Explanation

To solve the problem of what product is formed when chloroform (CHCl3) reacts with sodium hydroxide (NaOH), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are chloroform (CHCl3) and sodium hydroxide (NaOH).

### Step 2: Understand the Reaction
Chloroform reacts with sodium hydroxide in a process known as hydrolysis. During this reaction, chloroform undergoes a transformation due to the presence of a strong base (NaOH).

### Step 3: Write the Reaction Equation
The reaction can be represented as follows:
\[ \text{CHCl}_3 + 4 \text{NaOH} \rightarrow \text{HCOONa} + 3 \text{NaCl} + 2 \text{H}_2\text{O} \]

### Step 4: Identify the Products
From the balanced equation, the products formed are:
- Sodium formate (HCOONa), which is the sodium salt of formic acid.
- Sodium chloride (NaCl).
- Water (H2O).

### Step 5: Conclusion
Thus, the main product of the reaction between chloroform and sodium hydroxide is sodium formate (HCOONa).

### Final Answer
When chloroform reacts with sodium hydroxide, it produces sodium formate (HCOONa), sodium chloride (NaCl), and water (H2O).

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