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Oxymercuration -demurcuration reaction of 1-methyl cyclohexene gives

A

cis-2-Methyl cyclohexene gives

B

trans-2-Methyl cyclohexanol

C

1-Methyl cyclohexanol

D

Mixture of cis and trans-2-methyl cyclohexanol.

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To solve the problem of the oxymercuration-demercuration reaction of 1-methylcyclohexene, we can follow these steps: ### Step 1: Understand the Reaction Mechanism The oxymercuration-demercuration reaction involves two main steps: 1. Oxymercuration: The alkene reacts with mercuric acetate (Hg(OAc)₂) in the presence of water to form a mercurial alcohol intermediate. 2. Demercuration: The mercurial intermediate is then treated with sodium borohydride (NaBH4) to remove the mercury and form the final alcohol product. **Hint:** Remember that oxymercuration follows Markovnikov's rule, where the more substituted carbon atom gets the -OH group. ### Step 2: Identify the Starting Material We start with 1-methylcyclohexene, which is a cyclic alkene with a methyl group attached to one of the carbon atoms in the ring. **Hint:** Visualize the structure of 1-methylcyclohexene to understand where the double bond and the methyl group are located. ### Step 3: Perform Oxymercuration In the oxymercuration step, mercuric acetate reacts with 1-methylcyclohexene. The double bond of the alkene attacks the mercury, leading to the formation of a cyclic mercurinium ion. Water then attacks the more substituted carbon of the mercurinium ion, resulting in the formation of a mercurial alcohol intermediate. **Hint:** Focus on the regioselectivity of the attack by water, which will lead to the formation of the more stable carbocation. ### Step 4: Perform Demercuration In the demercuration step, the mercurial alcohol intermediate is treated with sodium borohydride (NaBH4). This step replaces the mercury with a hydrogen atom, yielding the final alcohol product. **Hint:** Remember that the demercuration step is crucial for removing the mercury and forming the final alcohol. ### Step 5: Identify the Final Product After completing the oxymercuration-demercuration reaction, the product formed is 1-methylcyclohexanol. This is the alcohol where the hydroxyl (-OH) group is added to the more substituted carbon of the original alkene. **Hint:** Check the structure of 1-methylcyclohexanol to confirm that the -OH group is correctly positioned. ### Final Answer The oxymercuration-demercuration reaction of 1-methylcyclohexene gives **1-methylcyclohexanol**.

To solve the problem of the oxymercuration-demercuration reaction of 1-methylcyclohexene, we can follow these steps: ### Step 1: Understand the Reaction Mechanism The oxymercuration-demercuration reaction involves two main steps: 1. Oxymercuration: The alkene reacts with mercuric acetate (Hg(OAc)₂) in the presence of water to form a mercurial alcohol intermediate. 2. Demercuration: The mercurial intermediate is then treated with sodium borohydride (NaBH4) to remove the mercury and form the final alcohol product. **Hint:** Remember that oxymercuration follows Markovnikov's rule, where the more substituted carbon atom gets the -OH group. ...
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Knowledge Check

  • Methylation of methyl amine gives

    A
    `(CH_(3))_(3) N`
    B
    `(CH_(3))_(2) NH`
    C
    `(CH_(3))_(4) N^(+) I`
    D
    All of these
  • Hydroboration oxidation of 3-methyl but-1-ene gives

    A
    3-methylbutan-2-ol
    B
    2-methylbutan-2-ol
    C
    3-methylbutan-1-ol
    D
    2-methylbutan-1-ol
  • What is the product of the reaction of methyl cyclohexene with BH_3 - THF followed by oxidation with alkaline H_2O_2 ?

    A
    II and III
    B
    II
    C
    III and IV
    D
    I and IV
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