When pentan-2-one is oxidised using conc. `HNO_(3)`, the major products formed will be

Options

A. n-Butyric acid and Formic acid
B. Isobutyric acid and Acetic acid
C. Pentanoic acid
D. Ethanoic acid and Propanoic acid.

Explanation

To solve the question of what major products are formed when pentan-2-one is oxidized using concentrated HNO3, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Pentan-2-one**:
- Pentan-2-one has a 5-carbon chain with a ketone (C=O) group at the second carbon position.
- The structure can be represented as:
```
CH3-CO-CH2-CH2-CH3
```

2. **Understand the Oxidation Reaction**:
- When pentan-2-one is oxidized with concentrated nitric acid (HNO3), it acts as a strong oxidizing agent.
- The ketone group (C=O) can be oxidized to form a carboxylic acid.

3. **Determine the Products of Oxidation**:
- The oxidation of the ketone group at the second carbon will lead to the formation of a carboxylic acid.
- The alkyl chain (the rest of the carbon chain) will also undergo oxidation, resulting in another carboxylic acid.

4. **Identify the Carboxylic Acids Formed**:
- The oxidation of the ketone group (C=O) at the second position will yield:
- From the ketone (2 carbon atoms): Ethanoic acid (CH3COOH).
- The oxidation of the remaining carbon chain (3 carbon atoms) will yield:
- From the alkyl chain (3 carbon atoms): Propanoic acid (C2H5COOH).

5. **Final Products**:
- Therefore, the major products formed from the oxidation of pentan-2-one using concentrated HNO3 are:
- Ethanoic acid (CH3COOH)
- Propanoic acid (C2H5COOH)

6. **Conclusion**:
- The correct answer is that the major products are Ethanoic acid and Propanoic acid.