Temperature pressure and molar concentration are the three factors which can disturb the equilibrium in a reversible reaction. Their effect is governed by Le Chatelier's principle . Whereas high concentration of the reactants always favours the formation of the products irrespective of its nature the effect of temperature and pressure depends upon the nature of the reaction . pressure does not disturb the equilibrium point in a reaction in which the reactants and products have same number of moles in the gaseous state.
In a closed system
`A (s) hArr 2B(g) +3C(g)`
if partical pressure of C is doubled then partial pressure of B will be :

Options

A. `2sqrt(2)` times the original value
B. `1/2` times the original value
C. 2 times of the original value
D. `(1)/(2sqrt(2))` times the original value.

Answer

D

Explanation

`K_(p) =p^(2) B xx p^(3)C`(first case) ,
`K_(p) = p^(2)B_(1) xxp^(3)C` (second case)
`p^(2)B xx p^(3)C =p^(2)B_(1) xx 8p^(3)C` ,
`(p^(2)B_(1))/(p^(2)B) =(8p^(2)C)/(8p^(3)C)=1/8`
`(pB_(1))/(pB) =sqrt((1)/(8)) , p B_(1) =(pB)/(2sqrt(2))`