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Aluminium forms [AIF(6)]^(3-) ion but bo...

Aluminium forms `[AIF_(6)]^(3-)` ion but boron does not form `[BF_(6)]^(3-)` ion. Explain.

Text Solution

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Boron can show a maximum valency as well as co-ordination number of four. Therefore it cannot form `[BF_(6)]^(3-)` ion where it is to exhibit co-ordination number six. On the other and, aluminium can extend its valency as well as co-ordination number to six due to the presence of vacant 3d orbitals. Therefore, it can form `[AIF_(6)]^(3-)` ion.
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Aluminium forms [AlF_(6)]^(3-) ion but boron does not form [BF_(6)]^(3-) ion.

Explain the following (a) Gallium has higher ionisation enthalpy than aluminium (b) Boron does not exist as B^(3+) ion (c) Aluminium forms [AlF_(6)]^(3-) ion but boron does not form [BF_(6)]^(3-) ion.

Knowledge Check

  • Aluminum forms [AIF_(6)]^(3-) but boron does not form [BF_(6)]^(3-) because

    A
    The atomic size of B is small
    B
    Of absence of d-orbital in B atom
    C
    Of high I.P B-atom
    D
    B is non -metal
  • Assertion (A) : Al forms [AlF_(6)]^(3-) ions but B does not form [BF_(6)]^(3-) ions. Reason (R) : B does not react with F_(2) .

    A
    Both A and R are true and R is the correct explanation of A
    B
    Both A and R are true but R is not a correct explanation of A
    C
    A is true but R is false
    D
    A is false but R is true
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    Explain the following : (a) Boron has high melting and boiling points. (b) The p pi - p pi back bonding occurs in the halides of boron and not in those of aluminimum. ( c) Boron and aluminium halides behave as Lewis acids. (d) Aluminium forms [AlF_(6)]^(3-) ion, but boron does not form [BF_(6)]^(3-) ion.

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    Why boron does not form B^(3+) ion?