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A voltaic cell is set up at 25^(@)Cwith ...

A voltaic cell is set up at `25^(@)C`with the following half cells :
`Al^(3+)`(0.001 M) and `Ni^(2+)`(0.50 M)
Write the equation for the reaction when the cell generates the electric current. Also determine the cell potential (Given `E_(Ni^(2+)//Ni)^(@)=-0.25 V, E_(Al^(3+)//Al)^(@)=-1.66 V)`.

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Identify the half-reactions and their standard reduction potentials. We have two half-cells: 1. Aluminum: \( \text{Al}^{3+} + 3e^- \rightarrow \text{Al} \) with \( E^\circ = -1.66 \, \text{V} \) 2. Nickel: \( \text{Ni}^{2+} + 2e^- \rightarrow \text{Ni} \) with \( E^\circ = -0.25 \, \text{V} \) ### Step 2: Determine which half-reaction will occur at the cathode and which at the anode. ...
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Knowledge Check

  • The following cell Al(s) | Al^(3+(aq, 0.001 M) || Cu^(2+)(aq, 0.10 M)| Cu(s) has a standard cell potential, E^(@) = 200V. What is the cell potential for this cell at the concentration given?

    A
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    B
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    C
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    D
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