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How many coloumbs are required for the o...

How many coloumbs are required for the oxidation of 1 mole of `H_(2)O "to" O_(2)`

Text Solution

Verified by Experts

`{:(H_(2)O rarr2H^(+) + 1//2 O_(2)+2e^(-)),(1 mol " "2 mol):}`
(Here, oxidation number of oxygen changes from -2 in `H_(2)O` to 0 in `O_(2)`. Therefore, 2 moles of electrons are lost during the oxidation of 1 mol of water.)
The charge Q on n mol of electrons is given by Q=nF
Thus, quantity of electricity required for oxidation of 1 mol of `H_(2)O "to" O_(2)`,
`Q=2 mol xx96500 "C mol"^(-1)=193000 C =1.93xx10^(5)C`.
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Knowledge Check

  • How many coulombs are required for the oxidation of 1 mol of H_(2)O to O_(2) ?

    A
    `93000C`
    B
    `1.93xx10^(5)C`
    C
    `9.65xx10^(40C`
    D
    `19.3xx10^(2)C`

  • How many coulombs are required for the oxidation of 0.01 mol of H_(2)O to O_(2) ?

    A
    `1.93 xx 10^(3) C`
    B
    `9.65 xx 10^(2) C`
    C
    `3.86 xx 10^(5) C`
    D
    `4.285 xx 10^(2) C`

  • How many coulombs are required for the oxidation of 1 mol of H_(2)O_(2) ?

    A
    93000C
    B
    `1.93xx10^(5)C`
    C
    `9.65xx10^(4)C`
    D
    `19.3xx10^(2)C`

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    Calculate the charge in coulombs required for the oxidation of: (i) 2 moles of H_(2)O to O_(2)

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    How many coulomb are required for the oxidation of "1 mol of "H_(2) O_(2)" to "O_(2) ?

    How many coulombs are required for oxidation of 1 mol H_(2)O to O_(2) ?

    How many coulombs of electricity are required for the oxidation of 1 mole of H_2O to O_2 ?

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