The specific conductance of 0.05 N solution of an electrolyte at 298 K is 0.002 S cm^(-1). Calculate the equivalent conductance.

Explanation

To solve the problem of calculating the equivalent conductance of a 0.05 N solution of an electrolyte with a specific conductance of 0.002 S cm^(-1) at 298 K, we can follow these steps:

### Step 1: Understand the Definitions
- **Specific Conductance (K)**: This is the conductance of a solution per unit length and area, given as 0.002 S cm^(-1).
- **Normality (N)**: This is defined as the number of gram equivalents of solute per liter of solution. In this case, we have a 0.05 N solution.

### Step 2: Calculate the Volume of Solution for 1 Gram Equivalent
- Since normality is defined as the number of gram equivalents per liter, we need to find out how much volume (V) contains 1 gram equivalent of the electrolyte.
...