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A block of mass 10 kg is suspended by th...

A block of mass 10 kg is suspended by three strings as shown in figure . Tension `T_(2)` is

A

100N

B

`(100)/(sqrt(3))N`

C

`sqrt(3)xx100N`

D

`50sqrt(3)N`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `T_(3) sin 60^(@)= T_(2) sin 30^(@)`
` therefore T_(3)=(T_(2))/(sqrt(3))`

W=100 N
Now, `T_(2) cos30^(@)+T_(3) cos 60^(@)=T_(1)=100`
or `(sqrt(3)T_(2))/(2)+(T_(2))/(sqrt(3))xx(1)/(2)=100 " or " (8T_(2))/(4sqrt(3))=100 " or " T_(2)=50sqrt(3)N`
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