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A body of mass 60 kg suspended by means ...

A body of mass 60 kg suspended by means of three strings, P, Q and R as shown in the figure is in equlibrium. The tension in the string P is

A

130.9 kgf

B

60 kgf

C

50 kgf

D

103.9 kgf

Text Solution

Verified by Experts

The correct Answer is:
D
(d) The given figure can be drawn as

Taking component of forces
`R cos theta = Mg implies R cos 60^(@)=Mg`….(i)
and `R sin 60^(@)=T` ….…(ii)
By Eqs. (i) and (ii), we get
` implies tan 60^(@)=(T)/(Mg) implies T=Mg tan 60^(@)`
or `T=60xxgxxsqrt(3)=103.9 kgf`
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