A thin bar magnet of length 2L is bent at the mid point, so that the angle between them is `60^(@)`.Find the new length of the magnet.
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On heating the magnet , the length of the magnet . `AC = AO _ OC = L "sin" ((theta)/(2)) + L "sin"((theta)/(2))` `2L "sin" 30^(@) = 2L xx (1)/(2) = L `
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