A bar magnet of length 0.1m has pole strength of 50A-m. Calculate the magnetic field at distance of 0.2m from tis centre on (i) its axial line and (ii) it equatorial line.
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Here, m=50A-m, r=0.2m, 2l=0.1m or l=0.05m Magnetic dipole moment, `" " M=m(2l)=50xx0.1=5A-m^(2)` `(i) B_("axial")=(mu_(0))/(4pi) (2Mr)/((r^(2)-l^(2)))=(10^(-7)xx2xx5xx0.2)/((0.2^(2)-0.05^(2))^(2))=1.42xx10^(-4)T` `(i) B_("equi")=(mu_(0))/(4pi) (2Mr)/((r^(2)+l^(2)))=(10^(-7)xx5)/((0.2^(2)-0.05^(2))^(2))` Formula with `(r^(2)-l^(2)) and (sigma^(2)rhol^(2))` are used become here `r gt gt l` does not apply.
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