A conducting square loop of side l and resistance R moves in its plane with a uniform velocity v perpendicular ot one of its sides. A uniform and constant magnetic field B exists along the perpendicualr ot the plane of the loop as shown in . The current induced in the loop is
(##HCV_VOL2_C38_E01_025_Q01##)

Options

A. `(Blv)/(R)`clockwise
B. `(Blv)/(R)` anti-clockwise
C. `(2Blv)/(R)` anti-clockwise
D. zero

Answer

A

Explanation

If the loop remains inside the region of magnetic field, no current will be induced. But, if it moves out of the plane, then the induced current is given by `i=(Blv)/(R)` and its direction will be clockwise (as per Lenz's law).