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In a series L-C-R circuit the voltage ac...

In a series L-C-R circuit the voltage across resistance , capacitance and inductance is 10 V each. If the capacitance is short circuited, the voltage across the inductance will be

A

10/`sqrt 2` V

B

10 V

C

10`sqrt 2` V

D

20 V

Text Solution

Verified by Experts

The correct Answer is:
A
`X_C` = `X_L` = R
V = `sqrt (V_R^(2) + (V_L - V_C)^(2))` but `V_L` = `V_C`
`therefore` V = `V_R` = 10
When capacitor is short circuited , `V_C` = 0
and `V_R` = `V_L`
`therefore` V = `sqrt V_(R)^(2) + V_(L)^(2)` or 10 = `sqrt 2V_L`
`thereforeV_L = 10/sqrt 2` V .
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