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Given the value of Rydberg constant is 1...

Given the value of Rydberg constant is `10^(7)m^(-1)`, the waves number of the lest line of the Balmer series in hydrogen spectrum will be:

A

`0.5xx10^(7) m^(-1)`

B

`0.25xx10^(7) m^(-1)`

C

`2.5xx10^(7) m^(-1)`

D

`0.025xx10^(4) m^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Given , Rydberg constant, `R=10^(7)m^(-1)`
`:.` for last line in Balmer series `n_(2)-oo,n_(1)=2`
As we know that,
`(1)/(lambda)=R((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))rArr(1)/(lambda)=10^(7)((1)/(2^(2))-(1)/(oo))`
`barv=(1)/(lambda)=(10^(7))/(4)=0.25xx10^(7)m^(-1)`
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Knowledge Check

  • The wave number of the H_(a)- line in Balmer series of hydrogen spectrum is

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    B
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  • If the wave number of 1^(st) line of Balmer series of H-atom is 'x' then :

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