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The half-life of radium is 1620 yr and i...

The half-life of radium is 1620 yr and its atomic weight is 226 kg per kilo mol. The number of atoms that will decay from its 1g sample per second will be (take, Avogadro's number, `N_(A)=6.023xx10^(23)` atom/kilo mol)

A

`3.61xx10^(10)`

B

`31.1xx10^(15)`

C

`3.6xx10^(12)`

D

`3.1xx10^(15)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) we have , `(dN)/(dt)=lamdaN`
and `lamda =(0.9631)/(T_(1//2))=(0.9631)/(1620xx365xx24xx60xx60)`
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Knowledge Check

  • The half-life of radium is 1620 years and its atomic weight is 226 . The number of atoms that will decay from its 1 g sample per second will be .

    A
    `3.6 xx 10^(10)`
    B
    `3.6 xx 10^(12)`
    C
    `3.1 xx 10^(15)`
    D
    `31.1 xx 10^(15)`

  • The half-life of radium is 1600 years . Calculate the number atoms that will decay from 1g sample of radium per second (given, atomic weight of radium = 226)

    A
    `3.6 xx 10^(10)`
    B
    7.2 xx 10^(10)`
    C
    `4.2 xx 10 ^(10)`
    D
    `14.6 xx 10^(10)`

  • Radium has atomic weight 226 and a half-life of 1600 Yr. The number of disintegrations produced per second from one gram are

    A
    `4.8xx10^(10)`
    B
    `9.2xx10^(6)`
    C
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    D
    zero

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