In a L-C circuit, angular frequency at resonance is `omega`. What will be the new angular frequency when inductor's inductance is made two times and capacitor's capacitance is made four times?

Options

A. `omega/2sqrt(2)`
B. `omega/sqrt(2)`
C. `2omega`
D. `(2omega)/(sqrt(2))`

Answer

A

Explanation

Angular frequency at resonance,
`omega = 1/sqrt(LC)`
According to question, when inductor's inductance is made 2 times and capacitance is 4 times, then
`omega^(') = 1/sqrt(LC)`
or `omega^(') = (1/(2sqrt(2)))1/sqrt(LC)`
`=omega/(2sqrt(2))` From Eq. (i)