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Calculate total energy of a particle of mass `2.0xx10^(-3)kg` oscillating simple harmonically with angular frequency `"0.45 rad s"^(-1)` and amplitude `1.0xx10^(-3)m`.

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Given, `m=2xx10^(-3)kg, omega="0.45 rad s"^(-1) and A =1xx10^(-3)m`.
We know that total energy `=(1)/(2)n omega^(2)A(2)=(1)/(2)xx2xx10^(-3)xx(0.45)^(2)(10^(-3))^(2)`
i.e. `E=2.025xx10^(-10)J`.
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