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A train starting from a railway station and moving with uniform acceleration attains a speed `40 km//h` in `10` minutes. Find its acceleration.

Text Solution

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Here,`" "` Initial speed of train, `u= 0 " "` (Starts from rest)
Final speed of train, `v= 40 ` km `h^(-1)`
`" "= (40xx100" m")/(60xx60" s")`
`" "= 11.11" m" s^(-1)`
And, `" "`Time taken, `t` = 10 minutes
`" "=10xx60` seconds
`" "= 600` s
Now, `" "` Acceleration, `a=(v-u)/(t)`
`" "a= (11.11-0)/(600)`
`" "a=(11.11)/(600)" m" s^(-2)` ltBrgt `" "a= 0.0185" m "s^(-2)" "(or 1.85xx10^(-2)" m" s^(-2))`
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