An electric oven of a `2kW` power rating is operated in a domestic circuit (220 V) that has a current rating of 5A. What results do you expect? Explain.

Answer

N/a

Explanation

We will first calculate the current drawn by this electric oven.
Now, `" "` Power, `P` = 2 kW
`" " = 2 xx 1000` W
= 2000 W
`" "` Potential difference or Voltage, `V` = 220 V
And, ` " "` Current drawn, `I` = ? `" "` (To be calculated)
Now, `" "` Power, `P = V+I`
So, `" " 2000 = 220 xx I`
And `" "` Current drawn, `I = (2000)/(220)`
= 9 A
Now, the current drawn by this electric oven is 9 amperes which is very high but the fuse in this circuit is only of 5 ampere capacity. So, when a very high current of 9 A flows through the 5 A fuse, the fuse wire will get heated too much, melt and break the circuit, cutting off the power supply. Thus, when a 2 kW power rating electric oven is operated in a circuit having 5 A fuse, the fuse will blow off cutting off the power supply in this circuit.