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Two particles A and B are performing SHM...

Two particles A and B are performing SHM along x and y-axis respectively with equal amplitude and frequency of `2 cm` and `1 Hz` respectively. Equilibrium positions of the particles A and B are at the coordinates `[3 cm, 0]` and `(0, 4 cm)` respectively. At `t = 0 ,B` is at its equilibrium position and moving towards the origin, while A is nearest to the origin and moving away from the origin-
Equation of motion of particle A can be written as-

A

`x = (2 cm) cos 2pit`

B

`x = (3 cm) - (2 cm) cos 2 pit`

C

`x = (2 cm) sin 2 pit`

D

`x = (3 cm) - (2 cm) sin 2pit`

Text Solution

Verified by Experts

The correct Answer is:
B

As A is at its negative extreme at `t = 0`
so `x - 3 = 2 sin (2pit + 3pi//2) rArr x = 3-2 cos (2pit)`
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Knowledge Check

  • Two particles A and B are performing SHM along x and y-axis respectively with equal amplitude and frequency of 2 cm and 1 Hz respectively. Equilibrium positions of the particles A and B are at the coordinates [3 cm, 0] and (0, 4 cm) respectively. At t = 0 ,B is at its equilibrium position and moving towards the origin, while A is nearest to the origin and moving away from the origin- Minimum and maximum distance between A and B during the motion is-

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