A star initially has 10^(40) deuterons....

A star initially has `10^(40) ` deuterons. It produces energy via the process `_(1)H^(2) + _(1)H^(2) + rarr _(1) H^(3) + p. `and `_(1)H^(2) + _(1)H^(3) + rarr _(2) He^(4) + n` .If the average power radiated by the state is `10^(16) W` , the deuteron supply of the star is exhausted in a time of the order of .
The masses of the nuclei are as follows:
`M(H^(2)) = 2.014 amu,`
`M(p) = 1.007 amu, M(n) = 1.008 amu, M(He^(4)) = 4.001 amu`.

`10^(6) s`

`10^(8) s`

`10^(22) s`

`10^(16) s`

Verified by Experts

The correct Answer is:

Add equation `3._(1)^(2)H rarr ._(2)^(4)HE + p + n`
(A) `Q = [-[m(._(2)^(4)He)+m(p) + m(n)] + 3m(._(1)^(2)H)] xx 931 MeV`
(B) `10^(16)W = (Q)/(t)`

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A star initially has 10^(40) deuterons it product energy via the process _(1)H^(2) + _(1)H^(2) + rarr _(1) H^(3) + p. and _(1)H^(2) + _(1)H^(3) + rarr _(2) He^(4) + n If the deuteron supply of the average power radiated by the state is 10^(16) W , the deuteron supply of the state is exhausted in a time of the order of . The masses of the nuclei are as follows: M(H^(2)) = 2.014 amu, M(p) = 1.007 amu, M(n) = 1.008 amu, M(He^(4)) = 4.001 amu.

`10^(6) s.`

`10^(8) s.`

`10^(12) s.`

`10^(16) s`.

`10^(6) s`

`10^(8) s`

`10^(12) s`

`10^(16) s`

(a) `10^6s`

(b) `10^8s`

(d) `10^16s`