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A particular hydrogen like atom has its ...

A particular hydrogen like atom has its ground state Binding energy `= 122.4 eV`. It is in ground state. Then

A

Its atomic number is 3

B

An electrom of `90` eV cam excite it

C

An electron of kinetic energy nearly `91.8 eV` can be brought to almost rest by this atom

D

An electron of kinetic energy `2.6 eV` may emerge from the atom when electron of kinetic energy 125 eV collides with this atom

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
`122.4 = (13.6Z^(2))/(1^(2)) rArr Z = 3, 91.8 = 122.4[1-(1)/(4)]`
So an electron of KE `91.8 eV` can transfer its energy to this atom.
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Knowledge Check

  • A particular hydrogen like atom has its ground state Binding energy = 122 eV . It is in ground state. Then

    A
    its atomic number is 3
    B
    An electron of 90 eV can excite it
    C
    An electron of kinetic energy 91.8 eV can be brought to almost rest by this atom
    D
    An electron of KE nearly 2.6 eV may emerge from the atom when electron of KE 125 eV collisions with this atom.

  • A hydrogen-like atom has ground state binding energy 122.4eV . Then :

    A
    its atomic number is `3`
    B
    an electron of `90 eV` can excite it to a higher state
    C
    an `80 eV` electron cannot excite it to a higher state
    D
    an electron of `8.2 eV` and a photon of `91.8 eV` are emitted when a `100 eV` electron interacts with it

  • The energy of a hydrogen like atom (or ion) in its ground state is -122.4 eV. It may be

    A
    hydrogen atom
    B
    `He^+`
    C
    `Li^(2+)`
    D
    `Be^(3+)`

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