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Cut off potential for a metal in photocl...

Cut off potential for a metal in photoclectric effect for light of wavelength `lambda_(1), lambda_(2)` and `lambda_(3)` is found to be `V_(1),V_(2)` and `V_(3)` volts , If `V_(1),V_(2)` and `V_(3` are in Arithmetic progression then `lambda_(1),lambda_(2)` and `lambda_(3)` will be in

A

Arithmetic Progression

B

Geiometric Progression

C

Harmonic Progression

D

None

Text Solution

Verified by Experts

The correct Answer is:
C
`eV_(1)=(hc)/lambda_(1) - phi, eV_(2)=(hc)/lambda_(2) - phi, eV_(3)=h_(0)/lambda_(3)-phi`
if `2V_(2)=V_(1)+V_(3) implies 2/lambda_(2)=1/lambda_(1)+1/lambda_(2)`
harmonic progression
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Knowledge Check

  • Cut off potentials for a metal in photoelectric effect for light of wavelength lambda_(1), lambda_(2) and lambda_(3) is found to be V_(1), V_(2) and V_(3) volts if V_(1), V_(2) and V_(3) are in Arithmetic Progression and lambda_(1), lambda_(2) and lambda_(3) will be :

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