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An electron collides with a fixed hydrog...

An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energy. Consequently the hydrogen atom may emit a photon corresponding to the largest wavelength of the Balmer series. The K.E. of colliding electron will be

A

`10.2 eV`

B

`1.9 eV`

C

`12.1 eV`

D

`13.6 eV`

Text Solution

Verified by Experts

The correct Answer is:
C
Excitation upto `n=3` is required so that visible length is emitted upon de-excitation.
So required energy `=13.6 (1-1/9)=12.1 eV`
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Knowledge Check

  • An electron with kinetic energy =E eV collides with a hydrogen atom in the ground state. The collision will be elastic

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    for all values of E
    B
    for `E lt 10.2 eV`
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    for `E lt 13.6 eV`
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    For all values of E
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    For `Elt10.2` eV
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    For `10.2 eV lt E lt13.6` eV only
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    For `0lt E lt 3.4` eV only

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