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Taking the Bohr radius a(0) = 53 pm, the...

Taking the Bohr radius `a_(0) = 53` pm, the radius of `Li^(++)` ion in its gnround state, on the basis of Bohr's model, will be about.

A

53pm

B

27pm

C

18pm

D

13pm

Text Solution

Verified by Experts

The correct Answer is:
C
Here, `a_0=53`pm `n=1` for ground state for `Li^(++)` ion, `Z=3` Radius of `n^(th)` orbit
`r=(n^2h^2)/(4pi^2mKZe^2)=(a_0n^2)/(Z)`
`therefore " "r=(53xx(1)^2)/(3)" "[becausea_0=(h^2)/(4pi^2mKe^2)=53]`
`=17.66 approx 18`pm.
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Knowledge Check

  • Taking the Bohr radius as r_(0)=53 pm, the radius of Li^( + +) ion in its ground state, on the basis of Bohrs model, will be a about

    A
    53pm
    B
    27pm
    C
    18pm
    D
    13pm

  • Find the radius of Li^(++) ions in its ground state assuming Bohr's model to be valid.

    A
    `12xx10^(-10)m`
    B
    `12xx10^(-12)m`
    C
    `16xx10^(-10)m`
    D
    `18xx10^(-12)m`.

  • What is the radius of the second orbit of helium atom , on the basis of Bohr's atom model ?

    A
    1.06 Å
    B
    2.12 Å
    C
    0.265 Å
    D
    0.53 Å

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