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The electron in a hydrogen atom makes a...

The electron in a hydrogen atom makes a transition from `n=n_(1)` to `n=n_(2)` state. The time period of the electron in the initial state `(n_(1))` is eigh times that in the final state `(n_(2))`. The possible values of `n_(1)` and `n_(2)` are

A

`n_1 = 8 , n_2=1`

B

`n_1 = 4 , n_2=2`

C

`n_1 = 2 , n_2 = 4`

D

`n_1 =1 , n_2 = 8`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • An electron in a hydrogen atom makes a transition from n_(1) to n_(2) . If the time period of electron in the initial state is eight times that in the final state then Find the ratio n_(1)/n_(2)

    A
    2
    B
    3
    C
    4
    D
    8

  • The electron in a hydrogen atom make a transtion n_(1) rarr n_(2) where n_(1) and n_(2) are the priocipal quantum number of the two states . Assume the Bohr model to be valid . The time period of the electron in the initial state is eight time that in the state . THe possible values of n_(1) and n_(2) are

    A
    `n_(1) = 4 , n_(2) = 2 `
    B
    `n_(1) = 8 , n_(2) = 2`
    C
    `n_(1) = 8 , n_(2) = 1 `
    D
    `n_(1) = 6 , n_(2) = 3`

  • An electron in hydrogen atom makes a transition n_i to n_2 where n_1 and n_2 are principal quantum numbers of the two states. Assuming Bohr's model to be valid the time period of the electron in the initial state is eight times that in the final state. The possible values of n_1 and n_2 are

    A
    `n_1 =4 and n_2 =2`
    B
    `n_1 = 6 and n_2 =2`
    C
    `n_1 =8 and n_2 =1`
    D
    `n_1 =8 and n_2 =2`

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