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One mL of an organic compound was dissol...

One mL of an organic compound was dissolved in ethanol and a very small drop of dilute alkali was added to it and them a drop of phenolphalein was added. The red colour of the indicator was seen . The mixture. was then heated . The colour disappeared in a few minutes . The organic compound is most likely to be

A

an aldehyde

B

a ketone

C

a carboxylic acid

D

an ester

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the steps and the reactions that occur when the organic compound is treated with ethanol, dilute alkali, and phenolphthalein. Here’s a step-by-step breakdown: ### Step 1: Understanding the Initial Setup 1. **Dissolving the Organic Compound**: We start with 1 mL of an organic compound dissolved in ethanol. Ethanol is a common solvent for organic reactions. **Hint**: Consider the properties of ethanol and how it interacts with different types of organic compounds. ### Step 2: Adding Dilute Alkali 2. **Adding Dilute Alkali**: A very small drop of dilute alkali (like NaOH) is added. This indicates that the organic compound may have acidic properties or can react with the alkali. **Hint**: Think about how different organic compounds (like acids, esters, etc.) would react with an alkali. ### Step 3: Adding Phenolphthalein 3. **Adding Phenolphthalein**: After adding the alkali, a drop of phenolphthalein is added, which turns red. This indicates that the solution is basic (pH > 8.2). **Hint**: Recall that phenolphthalein is an acid-base indicator that changes color based on the pH of the solution. ### Step 4: Heating the Mixture 4. **Heating the Mixture**: The mixture is then heated, and the red color disappears after a few minutes. This disappearance of color suggests that the alkali is being consumed in a reaction. **Hint**: Consider what reactions could occur upon heating that would consume the alkali and lead to a change in pH. ### Step 5: Identifying the Organic Compound 5. **Analyzing the Reaction**: The disappearance of red color indicates that the alkali (NaOH) is reacting with the organic compound. If the organic compound were a carboxylic acid, the alkali would neutralize it, but phenolphthalein would not show red initially with a carboxylic acid. Thus, it cannot be a carboxylic acid. **Hint**: Think about the hydrolysis of esters in the presence of a base and how this would affect the pH. ### Conclusion 6. **Final Identification**: The organic compound is most likely an ester. When heated with dilute alkali, the ester undergoes hydrolysis to form a sodium salt of the corresponding carboxylic acid and alcohol, consuming the alkali and causing the red color to disappear. **Final Answer**: The organic compound is most likely an ester.
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Knowledge Check

  • Certain organic compound dissolves readily in H_2 SO_4 and also gives violet colour with FeCl_3 (aq). The compound is most likely

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    Isopropy alcohol
    B
    Viny alcohol
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    `PbCr_(2)O_(7)`
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    `PbCrO_(4)`
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    `Pb(FeO_(2))_(2)`
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    A
    `Fe(OH)_(3)`
    B
    `Cr(OH)_(3)`
    C
    `Pb(OH)_(2)`
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