Home
Class 12
CHEMISTRY
An excited hydrogen atom returns to the ...

An excited hydrogen atom returns to the ground state . The wavelength of emitted photon is ` lambda` The principal quantum number of the excited state will be :

A

`[(lambdaR)/(lambdaR-1)]^(1//2)`

B

`[(lambdaR+1)/(lambdaR)]^(1//2)`

C

`[lambdaR(lambdaR+1)]^(1//2)`

D

`[(1)/(lambdaR(lambdaR+1))]^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NTA JEE MOCK TEST 84

    NTA MOCK TESTS|Exercise CHEMISTRY|25 Videos

  • NTA JEE MOCK TEST 86

    NTA MOCK TESTS|Exercise CHEMISTRY|25 Videos

Similar Questions

Explore conceptually related problems

An excited state of H atom emits a photon of wavelength lamda and returns in the ground state. The principal quantum number of excited state is given by:

A gas of hydrogen - like ion is perpendicular in such a way that ions are only in the ground state and the first excite state. A monochromatic light of wavelength 1216 Å is absorved by the ions. The ions are lifted to higher excited state and emit emit radiation of six wavelength , some higher and some lower than the incident wavelength. Find the principal quantum number of the excited state identify the nuclear charge on the ions . Calculate the values of the maximum and minimum wavelengths.

Knowledge Check

  • An excited hydrogen atom returns to the ground state . The wavelength of emittted photon is lambda The principal quantium number fo the excited state will be :

    A
    ` [(R+1)/(lambdaR)]^(2//2)`
    B
    `[lambdaR (lambdaR + 1) ]^(1//2)`
    C
    ` [(R+1)/(lambdaR-1)]^(2//2)`
    D
    `[1/(lambdaR (lambdaR+1))]^(1//2)`

  • Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength lambda . If R is the Rydberg constant, then the principal quatum number n of the excited state is

    A
    `sqrt((lambdaR)/(lambdaR-1))`
    B
    `sqrt((lambda)/(lambdaR-1))`
    C
    `sqrt((lambdaR^2)/(lambdaR-1))`
    D
    `sqrt((lambdaR)/(lambda-1))`

  • when a hydrogen atom is raised from the ground state to an excited state

    A
    `P.E.` increases and `K.E.` decreases
    B
    `P.E.` decreases and `K.E.` increases
    C
    Both kinetic energy and potential eenrgy increase
    D
    Both `K.E.` and `P.E`. Decrease

    • Similar Questions

    Explore conceptually related problems

    A gas of hydrogen like ions is prepared in a particular excited state A. if emit photons having wavelength equal to the wavelength of the first line of the lyman series together with photons of five other wavelength identify the gas and find the principal quantum number of the state A

    When a hydrogen atom is raised from the ground state to an excited state

    An excited hydrogen atom emits a photon of wavelength lambda in returning to the ground state. If R is the Rydberg constant, then the quantum number n of the excited state is

    An excited hydrogen atom emits a photon of wavelength lambda in returning to the ground state. If 'R' is the Rydberg's constant, then the quantum number 'n' of the excited state is:

    The value of wavelength radiation emitted by an H -atom, if atom is excited to state with principal quantum number four is :

    Home
    Profile