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Spin magnetic moment of X^(n+) (Z=26) is...

Spin magnetic moment of `X^(n+) (Z=26)` is `sqrt(24) B.M.` Hence number of unpaired electrons and value of `n` respectively are:

A

4,2

B

2,4

C

3,1

D

0,2

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • Magentic moment of Fe^(a+)(Z= 26 ) is sqrt 24 BM . Hence muber of unpaired electron and value lf a respectively are :

    A
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    B
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    C
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    D
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  • Number of unpaired electrons in N^(2+) is/are

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    B
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    C
    1
    D
    3

  • Number of unpaired electrons in Fe^(3+) (Z = 26) is

    A
    0
    B
    2
    C
    3
    D
    5

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