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Treatment of (+)- glucose with HIO(4) gi...

Treatment of `(+)-` glucose with `HIO_(4)` gives results that confirm its aldohexose structure. What product should be formed, and how much `HIO_(4)` should be consumed.

Text Solution

Verified by Experts

Since in glucose there are five `-Oll` groups so five moles of `HlO_(4)` are consumed giving main product formic acid and formaldehyde as shown below :
`"Glucose"+5HlO_(4) to 5HCOOH+HCHO`.
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alpha -glucose is oxidized by HIO_(4) more rapidly than its beta -anomer at the 1-2 bond.

Compound AC_5H_(10)O_4 , is oxidized by Br_2 - H_2O to the acid, C_5H_(10)O_(5) . (A) Forms a triacetate (Ac_(2)O) and is reduced by HI to n-pentane. Oxidation of (A) with HIO_(4) gives, among other product, 1 molecule of CH_2O and 1 molecule of HCO_(2)H . What are the possible structures or (A) and how could you distinguish between them?

Knowledge Check

  • The open - chain glucose on oxidation with HIO_(4) gives

    A
    `5HCOOH+H_(2)C=O`
    B
    `4HCOOH+2H_(2)C=O`
    C
    `3HCOOH+3H_(2)C=O`
    D
    `2HCOOH+4H_(2)C=O`

  • What is formed when glycerol reacts with HIO_(4) ?

    A
    Two molecules of formic acid and one molecule of formaldehyde
    B
    Two molecules of formaldehyde and one molecule of formic acid
    C
    Three molecules of formic acid
    D
    Three molecules of formaldehyde

  • D-Glucose overset(5HIO_4)(to) Product is

    A
    `4HCO_2H_1CO_2, HCHO`
    B
    `5HCO_2H, HCHO`
    C
    `4HCO_2H_1CO_2, HCHO`
    D
    `5HCHO,HCO_2H`

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    Two vectors of magnitudes 3 and 4 give a resultant of magnitude 1. What must be the dot product of these two vectors ?

    The product X on oxidation with HIO_4 gives :

    When glucose is treated with an execss of HIO_(4) , the products formed are

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