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Cl -overset(O) overset(||)C-OC(2)H(5)- o...

`Cl -overset(O) overset(||)C-OC_(2)H_(5)- overset((1)'X'RMgX) underset((2)NH_(4)Cl)to 3^(@)"alcohol"`

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The correct Answer is:
`0.50`
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Explore conceptually related problems

Cl-overset(O)overset(||)C-OC_(2)H_(5)overset((1)'X'RMgX)underset(NH_(4)Cl)rarr3^(@) Alcohol. Find out value of 'X'.

Cl-overset(O)overset(||)C-OC_(2)H_(5)underset(CH_(3)MgBr)overset(1"mole")toAunderset(1"mole")overset(CH_(3)MgBr)toBunderset(H_(2)O)overset(CH_(2)MgBr)toCoverset(H^(+)//Delta)toD

Knowledge Check

  • CH_(3)-CH_(2)-overset(O)overset(||)(C )-OC_(2)H_(5) overset(Naoverset(**)(O)H)underset(H_(2)O^(**))rarr Products of the above reaction contain

    A
    `CH_(3)-CH_(2)-overset(O)overset(||)(C )-overset(**)(O^(-))`
    B
    `CH_(3)-CH_(2)-overset(O^(**))overset(||)(C )-O^(-)`
    C
    `CH_(3)CH_(2)-overset(**)(O)-H`
    D
    Both (a) and (b)

  • CH_(3)MgX underset(H^(+),H_(2)O)overset(CH_(3)-overset(O)overset(||)(C)-OC_(2)H_(5))(rarr)(A)overset(Na)(rarr)(B)overset(C_(2)H_(5)OH)(rarr)(C ),(C ) is :

    A
    `CH_(3)-overset(O)overset(||)(C)-CH_(3)`
    B
    `(CH_(3))_(3)C-O-C_(2)H_(5)`
    C
    `C_(2)H_(5)OC_(2)H_(5)`
    D
    `CH_(3)-overset(O)overset(||)(C)-OC_(2)H_(5)`

  • HOCH_(2)CH_(2)CH_(2)-overset(O)overset(||)(C)-OCH_(2)CH_(3) overset(PC C)(to) (A) underset((1 "molar equivalent"))overset(H_(2)C = CHMgBr)(to) (B) overset(NH_(4)Cl//H_(2)O)(to)(C)overset(KOH)underset(H_(2)O)(to)overset(H_(3)O^(o+))(to) underset("Pyridine")overset((CH_(3)-overset(O)overset(||)(C))_(2)O)(to)(D) Product (D) is :

    A
    B
    `H_(2)C=CH-CH_(2)-underset(OH)underset(|)(C)-CO_(2)H`
    C
    `H_(2)C= CH-underset(OH)underset(|)(C)-CH_(2)-overset(O)overset(||)(C)-O-overset(O)overset(||)(C)-CH_(3)`
    D
    `H_(2)C=CH-CH_(2)-underset(OH)underset(|)(CH)-CH_(2)-overset(O)overset(||)(C)-O-H`

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    Write IUPAC Name : (a) CH_(3)-CH_(2)-underset(CH_(3))underset(|)underset(CH_(2))underset(|)CH-overset(O)overset(||)C-OCH_(3) (b) CH_(3)-underset(" "CH=CH_(2))underset(|)(CH)-CH_(2)-overset(O)overset(||)C-OC_(2)H_(5) (c) > CH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)C-overset(" "overset(O)overset(||)C-NH_(2))overset(|)(CH)-underset(CH_(3))underset(|)(CH)-CH_(3)

    The number of -OH groups present in the end product. H-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-Cl underset((ii)." "H_(2)O)overset((i)." "NaBH_(4))to

    Complete the following (i) CH_(3)-CH_(2)-overset(O)overset(||)(C)-CHBr_(2) overset((i) NaOBr)underset((ii) H^(+)) to (ii) C_(6)H_(5)-C_(6)H_(5)-CH_(3) overset(Cl_(2)//hv)to (A) overset(H_(2)O // OH^(+)) to (B)

    CH_(3)-overset(O)overset(||)(C)-CH_(2)-CH_(2)-overset(O)overset(||)(C)-CH_(3) overset((NH_(4))_(2)CO_(3))underset(Delta) to (A) overset(C Cl_(3) CO_(2)Na) underset(Delta) to underset(("major"))((B)) Product (B) of above reaction is :

    C_(6) H_(5) (CH_(2))_(5) overset(O)overset(||)(C) - Cl underset(CS_(2))overset(AlCl_(3))rarr underset(C_(12) H_(14)O)((A)) underset(H_(3)O^(oplus))overset(KMnO_(4), D)rarr (B) , Compound (B) is:

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