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A sample of AgCI was treated with 5.00mL...

A sample of AgCI was treated with `5.00mL` of `1.5M` `Na_(2)CO_(3)` solubility to give `Ag_(2)CO_(3)` . The remaining solution contained `0.0026g of CI^(-)` per litre. Calculate the solubility product of AgCI. `(K_(SP)for Ag_(2)CO_(3)=8.2xx10^(-12))`

Text Solution

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`1.71 xx10^(-10)`
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A sample of AgCl was treated with 5.00 ml of 1.5 M Na_(2)CO_(3) solution to give Ag_(2)CO_(3) . The remaining solution contained 0.0026 g of Cl^(-) per litre. Calculate the solubility product of AgCl (K_(sp) "for" Ag_(2)CO_(3)=8.2xx10^(-2))

A sample of AgCl was treated with 5.0mL of 1.5 M Na_(2)CO_(3) solution to give Ag_(2)CO_(3). The remaining solution contained 0.0026 g of Cl^(-) per litre. Calculate the solubility product of AgCl. [K_(sp) (Ag_(2)CO_(3))=8.2 xx 10^(-12)]

Knowledge Check

  • The expression for the solubility product of Ag_(2)CO_(3) will be :

    A
    `K_(sp)=s^(2)`
    B
    `K_(sp)=4s^(3)`
    C
    `K_(sp)=27s^(4)`
    D
    `K_(sp) = s`

  • Na_(2)CO_(3)+AgNO_(3) to Ag_(2)CO_(3)darr+NaNO_(3)

    A
    For coloured ppt./Black ppt
    B
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    C
    for clear/colourless solution
    D
    For white ppt.

  • Na_(2)CO_(3)+AgNO_(3) to Ag_(2)CO_(3)darr+NaNO_(3)

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    C
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    D
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