Home
Class 12
CHEMISTRY
In a zinc manganese dioxide dry cell, th...

In a zinc manganese dioxide dry cell, the anode is made up of zinc and cathode of a carbon rod surrounded by a mixture of `MnO_(2)`, carbon `NH_(4)Cl and ZnCl_(2)` in aqueous base.
The cathodic reaction may be represented as:
`2MnO_(2) (s) + Zn^(2+) + 2e^(-) rarr ZnMn_(2) O_(4) (s)`
Let there be 8g `MnO_(2)` in the cathodic compartment. How many days will the dry cell continue to give a current of `4 xx 10^(-3)` ampere ?

Text Solution

Verified by Experts

The correct Answer is:
25.675 day
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    FIITJEE|Exercise Assignment Problems (Objective) Level-1|50 Videos

  • ELECTROCHEMISTRY

    FIITJEE|Exercise Assignment Problems (Objective) Level-1 Reasoning Type Questions|6 Videos

  • ELECTROCHEMISTRY

    FIITJEE|Exercise Assignment Problems (Subjective) Level-1 (Numerical Problems)|8 Videos

  • CONCEPT OF ACIDS AND BASES

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|4 Videos

  • ELECTROPHILIC AROMATIC SUBSTITUTION

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS INDICATED BY DIGITAL INTERGER|1 Videos

Similar Questions

Explore conceptually related problems

In a zinc manganese dioxide dry cell, the anode is madeup of Zn1 and cathode of carbon rod surrounded by a mixture of MnO_(2) , carbon, NH_(4)Cl , and ZnCl_(2) in aqueous base. The cathodic reaction is : ZnMnO_(2)(s)+Zn^(2+)+2e^(-) rarr ZnMn_(2)O_(4)(s) 8.7g of MnO_(2) is taken in the cathodic compartment. How many days will the dry cell continue to give a current of 9.65xx10^(-3)A ? ( Atomic weight of Mn=55)(Mw of MnO_(2)=87g mol^(-1))

The cathodic reaction of a Zn - MnO_2 dry cell is represented as 2 MnO_2(s) + Zn^(2+) + 2e = Zn MnO_4(s) . If there is 8.0 g MnO_2 present in the cathodic chamber, how long will the cell function to supply 4 xx 10^(-3) ampere of current?

Knowledge Check

  • The cathodic reaction of a dry cell is represented as 2MnO_(2)(s)+Zn^(2+)+2e^(-) rarr ZnMn_(2)O_(4) (s) If there are 8 g MnO_(2) in the cathodic compartment then the time for which the dry cell will continue to give current of 2 milliampere, is

    A
    25.675 day
    B
    51.35 day
    C
    12.8 day
    D
    6.423 day

  • In a cell that has the reaction Zn(s) + 2H^(+) (aq) rarr Zn^(2+) (aq) + H_(2) (g) , addition of H_(2) SO_(4) to cathode compartment, will:

    A
    increase the `E_(cell)` and shift the equilibrium to the left
    B
    lower the `E_(cell)` and shift the equilibrium to the right
    C
    increase the `E_(cell)` and shift the equilibrium to the right
    D
    lower the `E_(cell)` and shift the equilibrium to the left

  • In the following equation, MnO_(2) acts as MnO_(4)^(2-) + 2H_(2)O + 2E^(-) rarr MnO_(2) + 4overset(Ө)(OH)

    A
    Oxidising agent
    B
    Reducing agent
    C
    Both oxidising and reducing agent.
    D
    Neither oxidising nor reducing agent.

    • Similar Questions

    Explore conceptually related problems

    MnO_(4)^(-) + SO_(2)^(2-) + H_(2)O = MnO_(2) + SO_(4)^(2-) + OH^(-)

    In the reaction C_(2) O_(4)^(-2) + MnO_(4)^(-) + H^(+) rarr Mn^(+2) +CO_(2) the reductants is -

    2mNo_(4)^(2-)+cl _(2) rarr Mn^(2+)+5Fe^(3+) MnO_(4)^(2-) can be converted to MnO_(4)^(-)

    In a cell that untillizes the reaction , Zn_((s)) + 2 H_((aq))^+ rarr Zn_((aq.))^(2+) + H_(2 (g) ) , adedition of H_2 SO_4 to cathode compartment will :

    The reaction, MnO_(4)^(2-) +e^(-)hArr MnO_(4)^(-) is shifted to right in

    Home
    Profile