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1 M benzoic acid (pK(a)=4.2) and 1 M C(6...

`1 M `benzoic acid `(pK_(a)=4.2)` and `1 M C_(6)H_(5)COONa` solutions are given separately. What is the volume of benzoic acid required to prepare a `93mL` buffer solution of `pH=4.5`?

Text Solution

Verified by Experts

`pH = pK_(a) + (log)([HCO_(3)^(-)])/([C_(6)H_(5)CO_(3)]) rArr 4.5 = 4.2 + log ((V_(2))/(V_(1))) rArr (V_(2))/(V_(1)) = 2`
`:.` volume of `C_(6)H_(5)COONa` required `= V_(@) = 62 mL`
volume of `C_(6)H_(5)COOH` required `= V_(1) = 31 mL`.
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Knowledge Check

  • 1 M benzoic acid (pK_a=4.20) and 1 M C_6H_5COONa solutions are given separately What is the volume of benzoic acid required to prepare a 300 ml buffer solution of pH =4.5 ? [log 2 =0.3]

    A
    200 mL
    B
    150 mL
    C
    100 mL
    D
    50 mL

  • What volume of 0.1 M HCOONa solution should be added to 50ml of 0.05 M formic acid to produce a buffer solution of pH=4.0 , pK_(a) of formic acid =3.7 ?

    A
    `50 ml`
    B
    `40 ml`
    C
    `30 ml`
    D
    `60 ml`

  • Fixed volume of 0.1M benzoic acid (pK_(a) = 4.2) solution is added into 0.2M sodium benzote solution and formed a 300mL , resulting acidic buffer solution. If pH of the resulting solution is 3.9 , then added volume of banzoic acid is

    A
    `240mL`
    B
    `150mL`
    C
    `100mL`
    D
    None