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What is the formula of iodide of Millon'...

What is the formula of iodide of Millon's base?

Text Solution

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`'OHg_(2)NH_(2)I`
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Explore conceptually related problems

Statement-1: Hg_(2)CI_(2) is blackened by NH_(3) due to the formation of iodide of Millon's base. Statement-2: Hg^(2+) ions give deep-red crystalline precipitate with cobalt (II) thiocyanate.

Hg_(2)Cl_(2) is black ened by NH_(3) due to formation of iodide of millon's base

Knowledge Check

  • Iodide of Million's base is

    A
    `H_(2)N*Hg_(2)O*HgI`
    B
    `H_(2)HgO*HgI_(2)C`
    C
    Both (a) and (b)
    D
    `H_(2)N*HgO*HgI`

  • The gas evolved in which of the following reactions forms the iodide of Millon's base on being passed through a solution of [HgI_(4)]^(2-) in KOH?

    A
    `CaSO_(4)` treated with dilute HCl
    B
    `NH_(4)Cl` boiled with NaOH
    C
    `ZnS` treated with dilute `H_(2)SO_(4)`
    D
    `MgCO_(3)` heated alone

  • What is the formula for finding the surface area of an open cylinder with base?

    A
    `2pi r h`
    B
    `pi r^(2) h`
    C
    `pi r (2h + r)`
    D
    `2pi r (h + r)`

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    (a) Ferric oxide crystallizes in a hexagonal close - packed array of oxide (O^(2-)) ions with two out of every three octahedral holes occupied by iron ions. What is the formula of ferric oxide ? (b) In cadium iodide every alternate octahedral hole in an HCP array of iodide I^(-) ions is occupied by a cadmium ion. What is the formula of cadium iodide.

    The formula of carbonate of a metal M is M_(2)CO_(3) . (a) What will be the formula of its iodide ? (b) What will be the formula of its nitride ? (c ) What will be the formula of its phosphate ?

    The number of mercury atoms in iodide of Millons base is x and the oxidation state of each mercury atom is y. Then (x+y) is

    The number of mercury atoms in iodide of Millons base is x and the oxidation state of each mercury atom is y. Then (x+y) is

    The molecular mass of iodide of tin (Sn) is 626.5 amu. What is the empirical formula of the substance? (I = 127, Sn = 118.5)

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