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STATEMENT-1: An alcohol does not react w...

STATEMENT-1: An alcohol does not react with halide ions as such but on dissolution in strong acids it does react strongly forming an alkyl halide.
and
STATEMENT-2: The strong acids accelerate the removal of proton from - OH group of the alcohol.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze both statements and determine their validity step by step. ### Step 1: Analyze Statement 1 **Statement 1:** An alcohol does not react with halide ions as such but on dissolution in strong acids, it does react strongly forming an alkyl halide. **Explanation:** - Alcohols, such as ethanol (C2H5OH), do not react directly with halide ions (like Cl⁻ or Br⁻) under normal conditions. - However, when an alcohol is mixed with a strong acid (for example, HCl), the acid donates a proton (H⁺) to the alcohol. This protonation of the -OH group converts it into a better leaving group (water, H2O). - As a result, the halide ion can then attack the carbon atom, leading to the formation of an alkyl halide (in this case, chloroethane, C2H5Cl). **Conclusion:** Statement 1 is true. ### Step 2: Analyze Statement 2 **Statement 2:** The strong acids accelerate the removal of proton from the -OH group of the alcohol. **Explanation:** - This statement implies that strong acids help in removing a proton from the -OH group of alcohols. - However, in the presence of a strong acid, the -OH group of the alcohol is protonated, which means it gains a proton rather than losing one. - The strong acid does not facilitate the removal of the proton from the -OH group; instead, it enhances the nucleophilicity of the alcohol by converting the -OH group into a better leaving group. **Conclusion:** Statement 2 is false. ### Final Conclusion - Statement 1 is true, and Statement 2 is false. - Therefore, the correct option is that Statement 1 is true and Statement 2 is false.
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Knowledge Check

  • Alcohol (ROH) does not react with NaBr to form alkyl bromide because

    A
    NaBr is in soluble in alcohol
    B
    `Br^(-)` is strong base than `OH^(-)`
    C
    NaBr is an ionic compound
    D
    `OH^(-)` is a strong base than `Br^(-)`
  • STATEMENT - 1 : Acetic acid does not undergo haloform reaction . and STATEMENT - 2 : Acetic acid has no alpha hydrogen .

    A
    STATEMENT -1 is True , STATEMENT -2 is True, STATEMENT -2 is a correct explanation for STATEMENT -1 .
    B
    STATEMENT -1 is True, STATEMENT-2 is True , STATEMENT -2 is NOT a correct explanation for STATEMENT - 1
    C
    STATEMENT -1 is True, STATEMENT - 2 is False .
    D
    STATEMENT -1 is False , STATEMENT -2 is True .
  • Alkyl halide reacts with alcoholic potassium hydrogen sulphide to form:

    A
    alkanethiol
    B
    thioether
    C
    thioacid
    D
    alkane
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