Home
Class 12
CHEMISTRY
STATEMENT-1: An alcohol does not react w...

STATEMENT-1: An alcohol does not react with halide ions as such but on dissolution in strong acids it does react strongly forming an alkyl halide.
and
STATEMENT-2: The strong acids accelerate the removal of proton from - OH group of the alcohol.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze both statements and determine their validity step by step. ### Step 1: Analyze Statement 1 **Statement 1:** An alcohol does not react with halide ions as such but on dissolution in strong acids, it does react strongly forming an alkyl halide. **Explanation:** - Alcohols, such as ethanol (C2H5OH), do not react directly with halide ions (like Cl⁻ or Br⁻) under normal conditions. - However, when an alcohol is mixed with a strong acid (for example, HCl), the acid donates a proton (H⁺) to the alcohol. This protonation of the -OH group converts it into a better leaving group (water, H2O). - As a result, the halide ion can then attack the carbon atom, leading to the formation of an alkyl halide (in this case, chloroethane, C2H5Cl). **Conclusion:** Statement 1 is true. ### Step 2: Analyze Statement 2 **Statement 2:** The strong acids accelerate the removal of proton from the -OH group of the alcohol. **Explanation:** - This statement implies that strong acids help in removing a proton from the -OH group of alcohols. - However, in the presence of a strong acid, the -OH group of the alcohol is protonated, which means it gains a proton rather than losing one. - The strong acid does not facilitate the removal of the proton from the -OH group; instead, it enhances the nucleophilicity of the alcohol by converting the -OH group into a better leaving group. **Conclusion:** Statement 2 is false. ### Final Conclusion - Statement 1 is true, and Statement 2 is false. - Therefore, the correct option is that Statement 1 is true and Statement 2 is false.
Promotional Banner

Topper's Solved these Questions

  • ALCOHOLS, ETHERS AND PHENOLS

    FIITJEE|Exercise MATCHING LIST TYPE QUESTIONS|2 Videos
  • ALCOHOLS, ETHERS AND PHENOLS

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|7 Videos
  • ALCOHOLS, ETHERS AND PHENOLS

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) (LEVEL-II)|17 Videos
  • ALDEHYDES AND KETONES

    FIITJEE|Exercise MATCHING LIST QUESTIONS|2 Videos

Similar Questions

Explore conceptually related problems

Alcohol (ROH) does not react with NaBr to form alkyl bromide because

Alcohols react with halogen acids as well as phosphorus halides to form haloalkanes but phenols do not form haloarenes. Explain.

Alkyl halide reacts with alcoholic potassium hydrogen sulphide to form:

STATEMENT-1: Tertiary butyl bromide and sodium ethoxide will react to form only ether. and STATEMENT-2: Ether are prepared by the reaction of alkoxides with alkyl halides.

STATEMENT -1: The addition of amines in aldehyde and ketone is carried out in weakly acidic medium STATEMENT -2 : In strong acidic medium amines will protonated the nucleophilic character of amine decrease.

When an alkyl halide reacts with alcoholic potassium hydroxide to form an alkene the reaction is called as :

Statement-1: NaCl cannot be hydrolysed. Statement-2: It is a salt of strong acid and strong base.