If the value of equilibrium constant for a particular reaction is `1.6xx10^(12)` , then art equilibrium the system will contain

Options

A. all reactants
B. mostly reactants
C. mostly products
D. similar amounts of reactants and products

Answer

C

Explanation

For a reaction.
`underset("Reactant")(A)hArr`underset("Product")(B)`
`K=([B])_(eq)/([A])_(aq)`
`1.6xx10^12=([B])_(eq)/([A])_(eq)`
`therefore [B]_(eq)gtgt[A]_(eq)`
So, mostly the product will be present in the equilibrium mixture.