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Given arrangement is in equilibrium and ...

Given arrangement is in equilibrium and elongation in spring is 1cm. Tension in string AD is `T_1`, in string BD is `T_2` and is string CD is `T_3`.Choose correct values of `T_1,T_2 and T_3`:

A

`T_1=80 N, T_2=50 N`

B

`T_1=80 N, T_2=30 N`

C

`T_1=80 N, T_3=70 N`

D

`T_1=80 N, T_3=100 N`

Text Solution

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The correct Answer is:
B,C
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Knowledge Check

  • If the arrangement in fig is given a downward acceleration then the ratio of tensions T_(1) and T_(2) is strings is-

    A
    `(m_(A)+m_(B))//m_(B)`
    B
    `(m_(A)+m_(B))//m_(A)`
    C
    `(m_(A)-m_(B))/(m_(A)+m_(B))`
    D
    None of these

  • ltbrltgt A string of mass m (can be non uniform as well) is suspended through two points which are not in same horizontal level. Tension in the string at the end points are T_(1) and T_(2) and at the lowest point is T_(3) . Mass of string in terms of T_(1),T_(2) and T_(3) can be represented a (uniform gravity 'g' exists downwards)

    A
    `(sqrt(T_(1)^(2)-T_(3)^(2))+sqrt(T_(2)^(2)-T_(3)^(2)))/(g)`
    B
    `((T_(1)+T_(2)-2T_(3)))/(g)`
    C
    `(sqrt(T_(1)^(2)+T_(2)^(2)))/(g)`
    D
    `(sqrt(T_(1)^(2)+T_(3)^(2))+sqrt(T_(2)^(2)+T_(3)^(2)))/(g)`

  • String-1 is connected with string-2 The mass per unit length in string-1 is mu _1 and mass per unit length in string-2 is 4mu _1. The tension in the strings is T .A travelling wave is coming from the left .What fraction of the energy in the incident wave goes into string-2?

    A
    `(1)/(8)`
    B
    `(4)/(9)`
    C
    ` (2)/(3)`
    D
    ` (8)/(9)`

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